Aggregation: "Has-a" Relationship

Easy Composition & Aggregation

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Problem Statement

Implement a `Player` class and a `Team` class. The `Team` class takes an existing `Player` pointer via a method `addPlayer(Player* p)`. Read a player name and team name, instantiate them separately, link them using the method, and print ‘[player] joined [team]’.

Input Format

Two strings: Player name then Team name.

Output Format

Print the formatted joining message.

Constraints

No spaces in names.

Sample Input

Alice Warriors

Sample Output

Alice joined Warriors

Explanation

Aggregation represents a weak 'has-a' relationship where the child object can exist independently of the parent, utilizing pointers.

Starter Code

#include <iostream>
#include <string>

class Player {
public:
    // Write your code here
};

class Team {
public:
    // Write your code here
};

int main() {
    // Create objects, use aggregation, and print
    return 0;
}

Limits

Time Limit: 1s
Memory Limit: 256MB

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