Write a C++ program using `std::binary_search` to check if a target exists in a sorted vector.
First line: N and Target. Second line: N sorted integers.
Print 'Present' or 'Absent'.
1 <= N <= 1000
5 30 10 20 30 40 50
Present
Binary search operates in $O(log N)$ time complexity on sorted ranges.
#include <iostream>
#include <vector>
#include <algorithm>
int main() {
int n, target;
if (std::cin >> n >> target) {
std::vector<int> vec(n);
for (int i = 0; i < n; i++) std::cin >> vec[i];
// Write your std::binary_search logic here
}
return 0;
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