Python does not have a strict `interface` keyword. Emulate one by creating an `IDataSource` ABC where *every* method (`connect`, `read`, `disconnect`) is abstract. Implement a `SQLDatabase` class fulfilling the contract. Print ‘SQL Connected’ in the connect method.
None
Print 'SQL Connected'.
None
SQL Connected
An interface is purely a contract defining what a class must do, containing absolutely zero concrete implementation.
import abc
class IDataSource(abc.ABC):
# Define abstract connect, read, and disconnect
pass
class SQLDatabase(IDataSource):
# Implement the interface
pass
if __name__ == '__main__':
db = SQLDatabase()
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