Write a C++ program using `std::unordered_map` to find indices of two numbers in an array that add up to a target sum.
First line: N and Target. Second line: N space-separated integers.
Print the two indices separated by a space.
2 <= N <= 1000
4 9 2 7 11 15
0 1
Hash maps achieve $O(N)$ time complexity for the Two Sum problem.
#include <iostream>
#include <unordered_map>
#include <vector>
int main() {
int n, target;
if (std::cin >> n >> target) {
// Write your Two Sum hash map logic here
}
return 0;
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