This example shows that the size of a pointer is independent of its type. All pointers store memory addresses, so their size depends on the system’s address width, not on the data type they point to.

#include <stdio.h>

int main()
{
    char *cptr;
    int *iptr;

    if (sizeof(cptr) == sizeof(iptr))
    {
        printf("Size of all pointers are equal\n");
    }
    else
    {
        printf("No, they are not equal\n");
    }

    if (sizeof(char *) == sizeof(long long *))
    {
        printf("Size of all pointers are equal\n");
    }
    else
    {
        printf("No, they are not equal\n");
    }

    return 0;
}

Output:
Size of all pointers are equal
Size of all pointers are equal

All pointers store addresses, so their size depends on the system architecture.

On a 32-bit system, pointer size is typically 4 bytes.
On a 64-bit system, pointer size is typically 8 bytes.

The type of the pointer (char *, int *, long long *) does not change the size of the pointer itself.

Pointer types are used to interpret the data during dereferencing, not to determine the size of the pointer.